# LOG#080. A Bug-Rivet “paradox”.

**Posted:**2013/04/07

**Filed under:**Physmatics, Relativity |

**Tags:**bug-rivet paradox, paradox, Relativity, special relativity Leave a comment

Imagine that an idealised bug of negligible dimensions is hiding at the end of a hole of length L. A rivet has a shaft length of .

Clearly the bug is “safe” when the rivet head is flush to the (very resiliente) surface. The problem arises as follows. Consider what happens when the rivet slams into the surface at a speed of , where c is the speed of light and . One of the essences of the special theory of relativity is that objects moving relative to our frame of reference are shortened in the direction of motion by a factor , where is generally called the Lorentz dilation factor, as readers of this blog already know. However, from the point of view (frame of reference) of the bug, the rivet shaft is even shorter and therefore the bug should continue to be safe, and thus fast the rivet is moving.

Apparently, we have:

**Remark:** this idea assumes that both objects are ideally rigid! We will return to this “fact” later.

From the frame of reference of the rivet, the rivet is stationary and unchanged, but the hole is moving fast and is shortened by the Lorentz contraction to

If the approach speed is fast enough, so that , then the end of the hole slams into the tip of the rivet before the surface

can reach the head of the rivet. The bug is squashed! This is the “paradox”:** is the bug squashed or not?**

There are many good sources for this paradox (a relative of the pole-barn paradox), such as:

1)http://en.wikipedia.org/wiki/Wikipedia:Reference_desk/Archives/Science/2006_October_19#Bug_Rivet_Paradox

2) A nice animation can be found here http://math.ucr.edu/~jdp/Relativity/Bug_Rivet.html

In this blog post we are going to solve this “paradox” in the framework of special relativity.

**SOLUTION**

One of the consequences of special relativity is that two events that are simultaneous in one frame of reference are no longer simultaneous in other frames of reference. *Perfectly rigid objects are impossible.*

In the frame of reference of the bug, the entire rivet cannot come to a complete stop all at the same instant. Information

cannot travel faster than the speed of light. It takes time for knowledge that the rivet head has slammed into the surface to

travel down the shaft of the rivet. Until each part of the shaft receives the information that the rivet head has stopped, that part keeps going at speed . The information proceeds down the shaft at speed c while the tip continues to move at speed .

The tip cannot stop until a time

after the head has stopped. During that time the tip travels a distance . The bug will be squashed if

This implies that

From we can calculate that

The bug will be squashed if the following condition holds

or equivalently, after some algebraic manipulations, the bug will be squashed if:

**Conclusion (in bug’s reference frame):** the bug will be definitively squashed when such as

**Check:** It can be verified that the limits and are valid and physically meaningful.

Note that the impact of the rivet head always happens** before** the bug is squashed.

In the frame of reference of the rivet, the bug is definitively squashed whenever .

Then,

or equivalently

or

where

The bug is squashed **before** the impact of the surface on the rivet head. This last equation (and thus ) is a velocity** higher** than .

**Conclusion (in rivet’s reference frame): **The entire surface cannot come to an abrupt stop at the same instant. It takes time for the information about the impact of the rivet tip on the end of the hole to reach the surface that is rushing towards the rivet head. Let us now examine the case where the speed is not high enough for the Lorentz-contracted hole to be shorter than the rivet shaft in the frame of reference of the rivet. *Now the observers agree that the impact of the rivet head happens first.* When the surface slams into contact with the head of the rivet, it takes time for information about that impact to travel down to the end of the hole. During this time the hole continues to move towards the tip of the rivet.

The time it takes for the propagating information to reach the tip of the stationary rivet is

during which time the bug moves a distance

In the rivet’s reference frame, therefore, The bug is squashed if the following condition holds

and then

and from this equation, we get same minimum speed that guarantees the squashing of the bug as was the case in the frame of reference of the bug! That is:

Note that observers travelling with each of the two frames of reference (bug and rivet) agree that the bug is squashed IF , and **that resolves the “paradox”**. They also agree that the impact of rivet head on surface happens before the bug is squashed, provided that the following condition is satisfied:

i.e., they agree if the impact of rivet head on surface happens **before** the bug is squashed

*Otherwise, they disagree on which event happens first. * For instance, if

For speeds this high, the observer in the bug’s frame of reference still deduces that the rivet-head impact happens first, but the other observer deduces that the bug is squashed first. This is consistent with the relativity of simultaneity!** At the critical speed,** when **the two events are simultaneous in the frame of the rivet**, (the river fits perfectly in the shortened hole), **but they are not simultaneous in the other frame of reference.**

See you in the next blog post!

# LOG#075. Batmobile “paradox”.

**Posted:**2013/02/11

**Filed under:**Physmatics, Relativity |

**Tags:**fake paradox, paradox, Relativity, simultaneity, special relativity Leave a comment

The Batmobile “fake paradox” helps us to understand Special Relativity a little bit. This problem consists in the next experiment:

There are two observers. Alfred, the external observer, and Batman moving with his Batmobile.

Now, we will suppose that the Batmobile is moving at a very fast constant speed with respect to the garage. Let us suppose that . Then, we have the following situation from the external observer:

However, with respect to the Batmobile reference frame, we have:

The question is. Who is right? Alfred or Batman? **The surprinsig answer from Special Relativity is that Both are correct.** Alfred and Batman are right! Let’s see why it is true. For Alfred, there is a time during which the Batmobile is completely inside the garage with both doors closed:

By the other hand, for Batman, the front and rear doors are not closed simultaneously! So there is never a time during which the Batmobile is completely inside the garage with both doors closed.

So, there is no paradox at all, if you are aware about the notion of simultaneity and its relativity!